{"id":2994,"date":"2023-12-05T10:00:07","date_gmt":"2023-12-05T01:00:07","guid":{"rendered":"https:\/\/winroadrikeijyuku.com\/oita\/?p=2994"},"modified":"2023-11-29T18:56:32","modified_gmt":"2023-11-29T09:56:32","slug":"%e6%9d%b1%e4%ba%ac%e5%a4%a7%e5%ad%a6%e3%81%ae%e6%95%b0%e5%ad%a6%e3%82%92%e8%a7%a3%e3%81%84%e3%81%a6%e3%81%bf%e3%81%9f","status":"publish","type":"post","link":"https:\/\/winroadrikeijyuku.com\/oita\/2023\/12\/05\/%e6%9d%b1%e4%ba%ac%e5%a4%a7%e5%ad%a6%e3%81%ae%e6%95%b0%e5%ad%a6%e3%82%92%e8%a7%a3%e3%81%84%e3%81%a6%e3%81%bf%e3%81%9f\/","title":{"rendered":"\u6771\u4eac\u5927\u5b66\u306e\u6570\u5b66\u3092\u89e3\u3044\u3066\u307f\u305f"},"content":{"rendered":"

\u3055\u3066\u3055\u3066\u3001\u5927\u5b66\u5165\u8a66\u6570\u5b66\u3078\u306e\u30a2\u30d7\u30ed\u30fc\u30c1\u2461\u3067\u767b\u5834\u3057\u305f\u6771\u4eac\u5927\u5b66\u6570\u5b66\u306e\u554f\u984c\u3002
\n\u305b\u3063\u304b\u304f\u306a\u306e\u3067\u89e3\u3044\u3066\u307f\u307e\u3057\u305f\u3002
\n\u3082\u3061\u308d\u3093\u3001\u3044\u308d\u3044\u308d\u3068\u8a66\u3057\u3066\u307f\u3066\u7d50\u8ad6\u3092\u66f8\u3044\u3066\u304a\u308a\u307e\u3059\u3002\u3068\u3066\u3082\u91cd\u8981\u306a\u89e3\u304d\u65b9\u304c\u542b\u307e\u308c\u3066\u3044\u307e\u3059\u306e\u3067\u3001\u30c1\u30a7\u30c3\u30af\u3057\u3066\u307f\u3066\u304f\u3060\u3055\u3044\u306d\u3002\u4ee3\u5165\u306a\u3093\u3066\u3057\u3061\u3083\u3063\u305f\u30899\u6b21\u65b9\u7a0b\u5f0f\u304c\u767b\u5834\u3057\u3061\u3083\u3044\u307e\u3059\u306e\u3067\u3001\u5f0f\u306e\u300c\u5bfe\u79f0\u6027\u300d\u3092\u5229\u7528\u3057\u3066\u89e3\u3044\u3066\u3044\u304f\u306e\u304c\u3088\u3044\u3067\u3059\u306d\u3002
\n\u5225\u89e3\u3082\u3042\u308a\u307e\u3059\u304c\u3001\u307e\u305a\u306f\u3053\u306e\u89e3\u6cd5\u3092\u7406\u89e3\u3057\u3066\u304f\u3060\u3055\u3044\u3002<\/p>\n

———————————————————————————————————
\n <\/p>\n

y = k(x-x3<\/sup>)\u30fb\u30fb\u30fb\u2460\u3000\u3000x = k(y-y3<\/sup>)\u30fb\u30fb\u30fb\u2461\u3000\u3068\u3059\u308b\u3002<\/p>\n

\u2460 + \u2461\u3088\u308a
\nx + y = k(x+y) – k(x3<\/sup>+y3<\/sup>)
\nx + y = k(x+y) – k(x+y)(x2<\/sup>-xy+y2<\/sup>)<\/p>\n

\u7b2c1\u8c61\u9650\u3060\u304b\u3089\u3001x > 0, y > 0 \u3064\u307e\u308a x+y > 0
\n\u3088\u3063\u3066
\n1 = k – k(x2<\/sup>-xy+y2<\/sup>)\u30fb\u30fb\u30fb\u2462<\/p>\n

\u2460 – \u2461\u3088\u308a
\n– (x-y) = k(x-y) – k(x3<\/sup>-y3<\/sup>)
\n– (x-y) = k(x-y) – k(x-y)(x2<\/sup>+xy+y2<\/sup>)<\/p>\n

\u03b1\u2260\u03b2\u3000\u3060\u304b\u3089 x\u2260y \u3064\u307e\u308a x-y\u22600
\n\u3088\u3063\u3066
\n– 1 = k – k(x2<\/sup>+xy+y2<\/sup>)\u30fb\u30fb\u30fb\u2463<\/p>\n

\u2462 – \u2463\u3088\u308a<\/p>\n

2 = 2kxy
\nxy = 1\/k\u30fb\u30fb\u30fb\u2464
\n\u307e\u305f\u3001\u2462\u3092\u5909\u5f62\u3057\u3066
\nk – k{(x + y)2<\/sup>-3xy} = 1
\n\u3053\u308c\u306b\u2464\u3092\u4ee3\u5165\u3059\u308b\u3068
\nk – k{(x + y)2 <\/sup>– 3\/k} = 1
\nk(x + y)2 <\/sup>= k + 2
\nk\u22600\u3060\u304b\u3089
\n(x + y)2 <\/sup>= 1+2\/k
\nx + y \u2260 0 \u306a\u306e\u3067
\nx + y = \u221a1+2\/k\u30fb\u30fb\u30fb\u2465<\/p>\n

x,y\u3092\u89e3\u306b\u6301\u3064t\u306e2\u6b21\u65b9\u7a0b\u5f0f\u3092\u8003\u3048\u308b\u3068
\nt2<\/sup>-(x+y)t+xy=0
\n\u2464,\u2465\u3088\u308a
\nt2 <\/sup>– (\u221a1+2\/k)t + 1\/k = 0
\n\u03b1\u2260\u03b2\u3088\u308a x,y \u304c\u7570\u306a\u308b2\u3064\u306e\u5b9f\u6570\u89e3\u3092\u3082\u3066\u3070\u3088\u3044\u306e\u3067D>0
\nD\uff1d(\u221a1+2\/k)2 <\/sup>– 4(1\/k) > 0
\n1 + 2\/k – 4\/k > 0
\nk>0\u3088\u308a\u3001\u4e21\u8fba\u306bk\u3092\u304b\u3051\u3066
\nk + 2 – 4 > 0
\n\u2234k>2<\/span><\/strong><\/p>\n

\"\"<\/p>\n","protected":false},"excerpt":{"rendered":"

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