\u554f\u984c<\/p>\n
\u200b\\( \\displaystyle I(a\u3001n)=\\int_0^{2\\pi}e^{ax}\\sin{nx}\\ dx \\)<\/span>\u200b\u306e\u3068\u304d\u200b\\( I(a\u3001n) \\)<\/span>\u200b\u3092\u6c42\u3081\u3088\u3002<\/p>\n \u666e\u901a\u306b\u90e8\u5206\u7a4d\u5206\u3059\u308c\u3070\u826f\u3044\u306e\u3067\u3059\u304c\u3001\u3053\u306e\u30bf\u30a4\u30d7\u306e\u7a4d\u5206\u306f\u6b21\u306e\u3088\u3046\u306b\u3059\u308b\u3068\u8a08\u7b97\u304c\u697d\u306b\u306a\u308a\u307e\u3059\u3002<\/span><\/p>\n \u3053\u306e\u5834\u5408\u6b21\u306e\uff12\u3064\u3092\u5fae\u5206\u3057\u3066\u8003\u3048\u307e\u3059\u3002<\/span><\/p>\n \u200b\\( (e^{ax}\\ \\sin{nx)’}=ae^{ax}\\sin{nx}+ne^{ax}\\cos{nx}\\dots \u2460 \\)<\/span>\u200b<\/span><\/p>\n \u200b\\( (e^{ax}\\ \\cos{nx)’}=ae^{ax}\\cos{nx}-ne^{ax}\\sin{nx}\\dots \u2461 \\)<\/span>\u200b<\/span><\/p>\n \u200b\\( \u2460\\times a-\u2461\\times n \\)<\/span>\u200b\u3088\u308a<\/span><\/p>\n \u200b\\( a(e^{ax}\\ \\sin{nx)’}=a^2e^{ax}\\sin{nx}+nae^{ax}\\cos{nx}\\\\-n(e^{ax}\\ \\cos{nx)’}=-nae^{ax}\\cos{nx}+n^2e^{ax}\\sin{nx} \\)<\/span>\u200b<\/span><\/p>\n \u3088\u3063\u3066<\/span><\/p>\n \u200b\\( (ae^{ax}\\sin{nx}-ne^{ax}\\cos{nx})’=(a^2+n^2)e^{ax}\\sin{nx} \\)<\/span>\u200b<\/span><\/p>\n \u200b\\( \\displaystyle I(a\u3001n)=\\int_0^{2\\pi}e^{ax}\\sin{nx}\\ dx=[\\displaystyle\\dfrac{ae^{ax}\\sin{nx}-ne^{ax}\\cos{nx}}{a^2+n^2}\\quad]_0^{2\\pi} \\)<\/span>\u200b<\/span><\/p>\n \u200b\\( =\\dfrac{-ne^{2a\\pi}+n}{a^2+n^2}=\\dfrac{n(1-e^{2a\\pi})}{a^2+n^2} \\)<\/span>\u200b<\/span><\/p>\n <\/p>\n \uff08\u5927\u5206\u7406\u7cfb\u5c02\u9580\u587eWINROAD <\/span>\u9996\u85e4\uff09<\/p>\n","protected":false},"excerpt":{"rendered":" \u554f\u984c \u200b\\( \\displaystyle I(a\u3001n)=\\int_0^{2\\pi}e^{ax}\\sin{nx}\\ dx \\)\u200b\u306e\u3068\u304d\u200b\\( I(a\u3001n) \\)\u200b\u3092\u6c42\u3081\u3088\u3002 \u666e\u901a\u306b\u90e8\u5206\u7a4d\u5206\u3059\u308c\u3070\u826f\u3044\u306e\u3067\u3059\u304c\u3001\u3053\u306e\u30bf\u30a4\u30d7\u306e\u7a4d<\/p>\n
\n